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# wllo iga jawaaba secx-cosx/secx=sin²x

wllo iga jawaaba secx-cosx/secx=sin²x
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2 Isticmaleyaal
2 Isticmaleyaal

1. Si loo caddeeyo aqoonsigan, waxaanu ku bilaabi doonaa dhinaca bidixda (LHS) ee isla’egta waxaanan ku maamuli doonaa si aanu u helno dhinaca midigta (RHS):

LHS: sex-cosx/sx

Talaabada 1: Isku-dar labada jajab adiga oo helaya qiimeeye guud. Qiimaha guud waa sexx, markaa waxaanu helnaa:

LHS: (secx – cosx)/sx

LHS: (sx – (1-sin²x))/sx

LHS: (sx – 1 + sin²x)/sx

LHS: ((sx/cosx) – 1 + sin²x)/sx

LHS: ((sx – cosx + cos²x)/cosx)/sx

LHS: ((sx – cosx + 1 – sin²x)/cosx)/secx

LHS: ((1 + sex – sin²x)/cosx)/sx

LHS: ((sex + secx – sin²x)/cosx)/sx

LHS: (2 – sin²x)/cosx²

Tallaabada 10: Isticmaal aqoonsiga sin²x = 1 – cos²x si aad ugu beddelato 1 – cos²x dembi²x ee tirada:

LHS: (2 – (1 – cos²x))/cosx²

LHS: (1 + cos²x)/cosx²

LHS: (1 + 1 – sin²x)/cosx²